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数据结构停车场管理问题的仿真算法程序,cpp实现的-data structure of the car park management simulation algorithm procedures to achieve the cpp
Date : 2008-10-13 Size : 1.34kb User : 张康

DL : 0
SSD5课程中使用栈来解决汽车停靠问题的代码,其余所需材料由实验包提供
Date : 2008-10-13 Size : 1.12kb User : 王鹏

数据结构停车场管理问题的仿真算法程序,cpp实现的-data structure of the car park management simulation algorithm procedures to achieve the cpp
Date : 2025-12-17 Size : 1kb User : 张康

控制小车自动寻找路径,可以以很快的速度过弯道,采用PID算法,能很好的完成自动调速-Control car automatically search for the path, can fast turn-off, using PID algorithm, the completion of a good automatic speed control
Date : 2025-12-17 Size : 270kb User : 李峰

DL : 0
SSD5课程中使用栈来解决汽车停靠问题的代码,其余所需材料由实验包提供-SSD5 courses used in the stack to solve the problem of call code, and the remaining materials required by the experimental package
Date : 2025-12-17 Size : 1kb User : 王鹏

DL : 0
车库 控制车入 车出的代码,显示 堆 和列的区别-car park car
Date : 2025-12-17 Size : 2.12mb User : jinjie

Car renatal management system simulation in C
Date : 2025-12-17 Size : 7kb User : wish_M

DL : 0
个人实现的上位机CAN程序,实现了汽车仪表通信功能。-Individuals to achieve PC CAN program and realize the car dashboard communications.
Date : 2025-12-17 Size : 1kb User : luqiang

DL : 0
用C++写的面向对象的程序,以停车场的管理为基础,对面向对象有很好的诠释-Written using C++ object-oriented programming to the car park management based on object-oriented interpretation of good
Date : 2025-12-17 Size : 704kb User : 苏庆贺

DL : 0
一个可以管理车辆中的车库中的车子的程序,可以正常的使用-Can manage the vehicles in a garage in the car program
Date : 2025-12-17 Size : 3kb User : shidongyuan

DL : 0
设停车场是一个可停放n辆车的狭长通道,且只有一个大门可供汽车进出。在停车场内,汽车按到达的先后次序,由北向南依次排列(假设大门在最南端)。-Parking lots is a car parked n the narrow channel, and only one gate for vehicle access. In the parking lot, the car arrived at the order, from north to south in order of priority (assuming the door at the southern tip.)
Date : 2025-12-17 Size : 2kb User : Chunhui

DL : 0
福建第四届盛群杯汽车电源箱的研究VB代码。基于串口通信。-Fujian fourth Cup car power box Holtek study VB code. Based on serial communication.
Date : 2025-12-17 Size : 288kb User : 韦增益

DL : 0
某汽车轮渡口,有n辆车要过河。n辆车只有两种要么是客车,要么是货车。已知过江渡船每次能载10辆车,从0分开始每10分钟来一次(即0分一辆,10分一辆,以此类推)。又知上渡船要遵守下述规定:若x分来了一辆渡船所有到大渡口时间<=x分且还没过河的车辆才可能上船,且客车先于货车上船,每上4辆客车必上1辆货车,这时若没有货车就上客车,若没有客车就上货车。试编写一个程序,模拟渡口的管理,统计客车和货车的平均等待时间。 输入格式: 第一行一个正整数n(1000 <= n <= 1000 000),表示要过江的车辆总数。 第二行到n+1行每行两个非负整数type,time(0 <= time <= 1000 000),表示time分到达渡口的车是type类型,type为0表示客车,为1表示货车,时间从0开始计,且按到达时间先后给出数据。 输出格式: 一行两个保留两位的小数(四舍五入)carWaitTime,trunkWaitTime以空格分开,carWaitTime表示客车的平均等待时间,trunkWaitTime表示货车的平均等待时间。-A car ferry port, there are n vehicles to cross the river. n is either the car only two buses, either truck. Known across the river ferry can carry 10 cars each, starting from 0 to once every 10 minutes (ie, 0 a, 10 a, and so on). They know on the ferry to comply with the following requirements: if x points to a car ferry to the large ferry all the time <= x min and it could not cross the river on board the vehicle, and passenger vehicles on board prior to each on the 4 buses will be on a truck, then if there is no vehicle on the bus, if there is no passenger on the truck. Try to write a program to simulate the management of the ferry, bus and truck statistical average waiting time. Input formats: The first line of a positive integer n (1000 <= n <= 1000 000), said the total number of vehicles to cross the river. The second line to the n 1 line per line two non-negative integer type, time (0 <= time <= 1000 000), said the time points to reach the ferry car is of ty
Date : 2025-12-17 Size : 2kb User : lijinping

DL : 0
智能汽车红外程序源代码,可实现红外测距等等功能-Smart car infrared source code
Date : 2025-12-17 Size : 75kb User : 张前海

基于博创公司的物联网小车平台开发的不停车收费系统,可以作为本科毕业设计,基于RFID技术,可以更换成图书馆管理系统,公司签到系统,建议使用SQLite数据库-Borch Internet of Things company car platform development is not a parking system, can be used as a graduate design, library management system based on RFID technology, can be replaced, the company attendance system, it is recommended to use the SQLite database
Date : 2025-12-17 Size : 2.09mb User :

DL : 0
wifi控制小车客户端,简单明了!可用。-wifi controlled car client, plain and simple! Available.
Date : 2025-12-17 Size : 1kb User : 刘文龙

sicily 1264,动态规划,计算最佳换轮胎方案,输出最短时间-Sicily 1264, dynamic programming, to calculate the best to change a tire program, the output shortest time
Date : 2025-12-17 Size : 1kb User : lin

数据结构课程设计,车辆租赁管理系统,实验说明,源代码,实验报告-Data structure curriculum design, vehicle rental management system, the experiment shows, source code, lab report
Date : 2025-12-17 Size : 310kb User : huguoqun

本代码实现的是一个简单的停车场管理系统。设停车场是一个可停放n辆汽车的狭长通道,且只有一个大门可供汽车进出。 汽车在停车场内按车辆到达时间的先后顺序,依次由北向南排列(大门在最南端,最先到达的第一辆车停放在停车场的最北端),若车场内已停满n辆汽车,则后来的车只能在门外的便道上等候,一旦有车开走,则排在便道上的第一辆车即可开入;当停车场内某辆汽车要离开时,在它之后进入的车辆必须退出车场为它让路,待该车辆开出大门外,其他车辆再按原次序进入车场,每辆停放在停车场的车在它离开停车场时必须按它停留时间的长短缴纳费用。试为停车场编制按上述要求进行管理的模拟程序。 基本要求为: 以栈模拟停车场,以队列模拟车场外的便道,按照从终端读入的输入序列进行模拟管理。每一组输入数据包括三个数据项:汽车“到达”或“离去”信息、汽车牌照号码以及到达或离去的时刻。对每一组输入数据进行操作后的输出信息为:若是车辆到达,则输出汽车在停车场内或便道上的停车位置;若是车辆离去,则输出汽车在停车场内停留的时间和应缴纳的费用(在便道上停留的时间不收费)。栈以顺序结构实现,队列以链表结构实现。-The implementation of the code is a simple car park management system. Suppose the parking is parked cars n the narrow channel, and only one door and out of cars. The arrival time of car in the car park by vehicle, followed by narrow (the door first to arrive at the southernmost tip of the first car in the garage, the northernmost), if the car floor is full of parked cars n , later the car can only wait on the sidewalk outside, once the car drove off, came in the first car on the sidewalk to open into when the parking of a vehicle to leave it incoming vehicles must exit the yard to make way for it to be the vehicle out outside the gate, other vehicles into the yard and then the original order, every car parked in the parking lot when it left the parking lot must stay the length of time to pay costs . Test according to the above requirements for the preparation of parking management simulation program. The basic requirements are: The stack analog Parking, to queue simulation car off
Date : 2025-12-17 Size : 237kb User : 丁洁琼

3D car code nice to use pls all try once and let me know
Date : 2025-12-17 Size : 513kb User : tiny
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