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[
Process-Thread
]
GetFileVersionInfo
DL : 0
封装文件版本获取的C++类,使用该类可以方便的获取一个可运行程序的属性信息。通过这个类可以方便的进行文件版本更新。-Packaging documents obtained C, the use of such convenient access to a procedure that can run the attribute information. Through this type can be conveniently updated versions of documents.
Date
: 2008-10-13
Size
: 5.06kb
User
:
cxingpeng
[
Process-Thread
]
mutildata
DL : 0
多线程序访问数据库-multi-lane access to the database procedures
Date
: 2025-12-22
Size
: 25kb
User
:
宋唯江
[
Process-Thread
]
GetFileVersionInfo
DL : 0
封装文件版本获取的C++类,使用该类可以方便的获取一个可运行程序的属性信息。通过这个类可以方便的进行文件版本更新。-Packaging documents obtained C, the use of such convenient access to a procedure that can run the attribute information. Through this type can be conveniently updated versions of documents.
Date
: 2025-12-22
Size
: 5kb
User
:
cxingpeng
[
Process-Thread
]
NetWork
DL : 0
利用多线程和IP帮助函数,获取局域网内主机IP,MAC地址和用户名。是学习多线程和IP扫描的好例子-The use of multi-threaded and IP help function, access to LAN host IP, MAC address and user name. Is to study multi-threaded IP scanning and a good example of
Date
: 2025-12-22
Size
: 1.19mb
User
:
陈煜
[
Process-Thread
]
cipandiaodu
DL : 0
1、对于如下给定的一组磁盘访问进行调度: 请求服务到达 A B C D E F G H I J K 访问的磁道号 30 50 100 180 20 90 150 70 80 10 160 2、要求分别采用先来先服务、最短寻道优先以及电梯调度方法进行调度。 3、要求给出每种算法中磁盘访问的顺序,计算出平均移动道数。 4、假定当前读写头在90号,向磁道号增加的方向移动。-1, for a given set of as disk access scheduling: Request service ABCDEFGHIJK access track to reach No. 30 50 100 1,802,090,150,708,010,160 2, the requests were a first-come, first served, shortest seek first, and elevator scheduling method of scheduling. 3, the algorithm required to give each disk access order to calculate the average number of mobile channel. 4, assuming that the current read-write head 90 to move the direction of increasing track number.
Date
: 2025-12-22
Size
: 1.16mb
User
:
刘莹
[
Process-Thread
]
HW3
DL : 0
c语言,多线程实现简单的终端处理器,读取文件,遇到特殊字符时采取相应操作 -A multi-threaded program using the pthread library. Your assignment is to write a program that emulates a simple terminal handler. The terminal handler process consists of three threads. Thread 1reads characters from input. In the input, some upper case letters represent control characters. Each character read by thread 1 is passed onto thread 2 before another is read. Thread 2 stores the characters as received. However, the following four characters are control characters that ask thread 2 to take action accordingly. B – erase last character from buffer L – insert an end-of-line marker into buffer C – remove contents of buffer U – remove current incomplete line from buffer The third thread, Thread 3, should read complete lines of characters (a line of character is complete, if it has an end-of-line character) from the buffer. Thread 3 should then print this line. Thread 2 should allow access only to completed lines in the buffer. You may assume that a completed line
Date
: 2025-12-22
Size
: 2kb
User
:
za
[
Process-Thread
]
sourcx
DL : 0
C源码Linux的nfsd存在溢出漏洞允许入侵者远程获取root-C source Linux NFSD exist exploit allows the invaders remote access to the root
Date
: 2025-12-22
Size
: 2kb
User
:
UNNcxmri!0924
[
Process-Thread
]
Automatsol-Automation
DL : 0
Access Automation Visual C++在vc++访问自动化,-Access Automation Visual c++ Access Automation in vc++,
Date
: 2025-12-22
Size
: 45kb
User
:
hnjvf
[
Process-Thread
]
dzutributldbackward
DL : 0
C + + access webservice using gsoap, combined with your articles
Date
: 2025-12-22
Size
: 121kb
User
:
jlgzawetb
[
Process-Thread
]
efaicrent
DL : 0
C源码Linux的nfsd存在溢出漏洞允许入侵者远程获取root(C source Linux NFSD exist exploit allows the invaders remote access to the root)
Date
: 2025-12-22
Size
: 2kb
User
:
Ojdeo
[
Process-Thread
]
vector
DL : 0
Access Automation from Visual C++在vc++访问自动化,()
Date
: 2025-12-22
Size
: 44kb
User
:
Jamkr
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