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[ComboBox] fchh DL : 0: 一．实验目的二．实验内容三、程序简要说明原文 : C语言词法分析器的设计与实现一．实验目的： 1．强化对系统软件综合工程实现能力、规划能力的训练； 2．加强对词法分析原理、方法和基本实现技术的理解；二．实验内容：用C语言(或 C++ )作为宿主语言完成： C语言(ANSI C或turbo C 2.0)词法分析器的设计和实现。三、程序简要说明： 1、属性字说明：共9种 KEYWORD: 关键字 \"auto\",\"break\",\"case\",\"char\",\"const\",\"continue\", \"default\",\"do\",\"double\",\"else\",\"enum\",\"extern\", \"float\",\"for\",\"goto\",\"if\",\"int\",\"long\",\"register\", \"return\",\"short\",\"signed\",\"sizeof\",\"static\",\"struct\", \"switch\",\"typedef\",\"union\",\"unsigned\",\"void\", \"volatile\",\"while\",\"include\"，\"define\" 共34个详见IsKeyWord（）函数 NUMBER：数字包括十进制整数，八进制整数，二进制整数，十六进制整数还可返回几种错误详见IsNumber（）函数 CONSTANT：常量宏定义标识符，不识别C++关键字const，简单处理一层宏定义。详见IsDefined（）函数 ...... 关键词 : 计算机编译原理 c语言词法分析器-one. Experiment 2. Experiment 3, procedures brief description of the original : C language lexical analyzer Design and Implementation of a. The experiment : 1. To strengthen the integrated system software engineering, planning capacity of training; 2. Lexical analysis on principle, and basic understanding of the technology; 2. Experiment : C (or C) as the host language completed : C language (ANSI C or Turbo C 2.0) lexical analyzer design and implementation. 3, brief description of procedures : 1, the word attribute : a total of nine species KEYWORD : keyword "auto" "break" and "case", "char", "const", "continue", "default", "do", "double", "else", "enum" "extern", "
Date : 2008-10-13 Size : 1.19kb User : 天空
[ComboBox] 耿5 DL : 0: oid move(char x,char y,struct H num[3]) /*Ò Æ ¯ µ Ä ¾ ß Ì å ¹ ý ³ Ì */ void hanoi(char x,char y,char z,int n,struct H num[3]) /*µ Ý ¹ é*/ void Init(void) /*³ õ Ê ¼ » ¯ */ void Close(void) /*Í ¼ Ð Î ¹ Ø ±Õ */ int computer=1 /*×Ô ¯ ¿ Ø Ö Æ Ó ë Ê Ö ¯ ¿ Ø Ö Æ µ Ä ±êÖ ¾ */ int speed=0 /*È « ¾ Ö ±ä Á ¿ speedÖ ÷Ò ª Ê Ç Ñ Ý Ê ¾ ¹ ý ³ Ì µ Ä Ë Ù È */-oid move (char x, y char, struct H num [3]) / * Ograve AElig Macr micro Auml frac34 szlig Igrave aring sup1 yacute sup3 Igrave * / void Hanoi (char x, char y, z char, int n, struct H num [3]) / * micro Yacute sup1 * / void Init (void) / * sup3 otilde Ecirc frac14 raquo Macr * / void Close (void) / * Iacute frac14 ETH Icirc sup1 Oslash Otilde * / int computer = 1 / * x Ocirc Macr Almost Oslash Ouml AElig Oacute euml Ecirc Ouml Macr Almost Oslash Ouml AElig micro Auml Ouml frac34 * / int speed = 0 / * Egrave laquo frac34 Ouml auml Aacute Almost speedOuml Ograve ordf Ecirc Ccedil Ntilde Yacute Ecirc frac34 sup1 yacute sup3 Igrave micro Auml Euml Ugrave Egrave * /
Date : 2008-10-13 Size : 25.16kb User : 耿敬东
[ComboBox] 耿5 DL : 0: oid move(char x,char y,struct H num[3]) /*Ò Æ ¯ µ Ä ¾ ß Ì å ¹ ý ³ Ì */ void hanoi(char x,char y,char z,int n,struct H num[3]) /*µ Ý ¹ é*/ void Init(void) /*³ õ Ê ¼ » ¯ */ void Close(void) /*Í ¼ Ð Î ¹ Ø ±Õ */ int computer=1 /*×Ô ¯ ¿ Ø Ö Æ Ó ë Ê Ö ¯ ¿ Ø Ö Æ µ Ä ±êÖ ¾ */ int speed=0 /*È « ¾ Ö ±ä Á ¿ speedÖ ÷Ò ª Ê Ç Ñ Ý Ê ¾ ¹ ý ³ Ì µ Ä Ë Ù È */-oid move (char x, y char, struct H num [3])/* Ograve AElig Macr micro Auml frac34 szlig Igrave aring sup1 yacute sup3 Igrave*/void Hanoi (char x, char y, z char, int n, struct H num [3])/* micro Yacute sup1*/void Init (void)/* sup3 otilde Ecirc frac14 raquo Macr*/void Close (void)/* Iacute frac14 ETH Icirc sup1 Oslash Otilde*/int computer = 1/* x Ocirc Macr Almost Oslash Ouml AElig Oacute euml Ecirc Ouml Macr Almost Oslash Ouml AElig micro Auml Ouml frac34*/int speed = 0/* Egrave laquo frac34 Ouml auml Aacute Almost speedOuml Ograve ordf Ecirc Ccedil Ntilde Yacute Ecirc frac34 sup1 yacute sup3 Igrave micro Auml Euml Ugrave Egrave* /
Date : 2026-01-09 Size : 25kb User :
[ComboBox] 13 DL : 0: 问题很简单。选择一个进制B，按照该进制将被乘数、乘数、乘积分别转换成十进制。然后判断等式是否成立。使得等式成立的最小-int alfafl a jalaw jal
Date : 2026-01-09 Size : 714kb User : 曹预建