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Search - paths problem - List
[
Windows Develop
]
path
DL : 0
探询路径 问题的提出:编写程序,输出下图的0至n(1<=n&&n>=9)的所有路径。 该题的核心是找出满足一定规律的递归条件,从而设计出递归算法。仔细分析不难发现规律: 0至n的路径由0至n-1的路径,加上n-1至n的路径,以及0至n-2的路径,加上n-2至n的路径这 两部分组成。即欲找0至n的路径,可以转化为找0至n-1及0至n-2的路径,这就可建立递归。-Explore the path Of the problem: the preparation of procedures, under the map output from 0 to n (1 <= n & & n> = 9) of all paths. The core of the problem is to find out the law to meet certain conditions recursive, so the design of recursive algorithm. Careful analysis of the law is not difficult to find: The path from 0 to n from 0 to n-1 of the path, together with n-1 to n path, as well as 0 to n-2 path, together with n-2 to n the path of this Composed of two parts.to find the path from 0 to n, can be transformed into looking for 0 to n-1 and 0 to n-2 path, which can establish a recursion.
Date
: 2025-12-18
Size
: 6kb
User
:
颜昌文
[
Windows Develop
]
migong_all_path
DL : 0
迷宫问题,完成的是一个现实中的迷宫游戏求最短路径及所有路径的问题,本程序相对于航班信息查询系统比较简单,主要包含使用系统迷宫(可以选择迷宫的入口和出口,并输出所有路径和最短路径),使用新建迷宫(可以自己设计迷宫的大小,及所有通路,可以选择迷宫的入口和出口,并输出所有路径和最短路径),用到了栈的使用,如栈的创建、入栈、出栈等函数功能。 -Maze problem, complete the maze is a real game for the shortest path and all paths of the problem, the program relative to the flight information inquiry system is relatively simple and mainly consists of a maze using the system (you can select the entry and exit the maze, and the output of all path and the shortest path), use the new labyrinth (maze can design the size, and all the channels, you can choose the maze entrance and exit, and output all the paths and the shortest path), use the stack to use, such as the creation of the stack, stack , the stack so the function function.
Date
: 2025-12-18
Size
: 9kb
User
:
lijin
[
Windows Develop
]
aodv
DL : 0
It is a reactive routing protocol, meaning that it establishes a route to a destination only on demand. In contrast, the most common routing protocols of the Internet are proactive, meaning they find routing paths independently of the usage of the paths. AODV is, as the name indicates, a distance-vector routing protocol. AODV avoids the counting-to-infinity problem of other distance-vector protocols by using sequence numbers on route updates, a technique pioneered by DSDV. AODV is capable of both unicast and multicast routing.
Date
: 2025-12-18
Size
: 3kb
User
:
吴建德
[
Windows Develop
]
qiqiaobansrc
DL : 0
C#七巧板-C#创建菱形图案,其间使用了进程,示例适用于 Windows 窗体,它需要 PaintEventArgse,一个 OnPaint 事件对象。代码执行下列操作: 创建两个路径:一个为头朝上的三角形,另一个为头朝下的三角形。将第二个路径添加到第一个路径上。将最终的路径绘制到屏幕。 设置控件样式为双缓冲,可以有效减少图片闪烁的问题-Create a diamond pattern C# tangram-C#, during which use of the process, the example applies to Windows Forms, and it requires PaintEventArgs e, an OnPaint event object. The code performs the following actions: create two paths: a head-on the triangle, another triangle upside down. Add a second path to the first path. Draw the final path to the screen. Set the control style for double buffering, the picture flashes can be effective in reducing the problem
Date
: 2025-12-18
Size
: 45kb
User
:
fwtb1
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