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AESCrypt30_source
Downloaded:0
Advanced Encryption Standard AES algorithm is a complete example of a rare.
Date
: 2025-06-29
Size
: 68kb
User
:
zmy
DelphiAES
Downloaded:0
A delphi language implementation of the Advanced Encryption Standard AES algorithm is an example.
Date
: 2025-06-29
Size
: 220kb
User
:
zmy
VBVigenere.ZIP
Downloaded:0
vigenere application
Date
: 2025-06-29
Size
: 62kb
User
:
vlad
actionscript3_MD5
Downloaded:0
actionscript3 md5 encrypted code
Date
: 2025-06-29
Size
: 3kb
User
:
Reamy
AES_128
Downloaded:0
128 bit Advanced Encryption Standard
Date
: 2025-06-29
Size
: 49kb
User
:
sri
RSA
Downloaded:0
Of their own design with a simple password lock ~ source code run the program ~
Date
: 2025-06-29
Size
: 5.18mb
User
:
高峰
CryptographyAndNetworkSecurity2005
Downloaded:0
Cryptography and network security
Date
: 2025-06-29
Size
: 37kb
User
:
minhchau
WRT54GP2
Downloaded:0
Market Common WRT54GP2 router voice gateway functionality break. .
Date
: 2025-06-29
Size
: 5.22mb
User
:
tandongsheng
DES
Downloaded:0
DES uses a 56-bit key and an additional 8-bit parity bit, resulting in the largest 64-bit packet size. This is an iterative block cipher, using the technology known as the Feistel, which will encrypt the text block half.
Date
: 2025-06-29
Size
: 1.96mb
User
:
ala
RSA
Downloaded:0
sadfjaslkdjaslj
Date
: 2025-06-29
Size
: 772kb
User
:
崔光涛
crypt_file
Downloaded:0
A kernel in the Window to encrypt files example.
Date
: 2025-06-29
Size
: 64kb
User
:
yudong
200601220942288253
Downloaded:0
首先选择一个随机数k, k与 p- 1互质,计算 a = g^k ( mod p ) 再用扩展 Euclidean 算法对下面方程求解b: M = xa+ kb ( mod p- 1 ) 签名就是( a, b )。随机数k须丢弃。 验证时要验证下式: y^a* a^b ( mod p ) = g^M ( mod p ) 同时一定要检验是否满足1<= a < p。否则签名容易伪造。 ElGamal用于加密。
Date
: 2025-06-29
Size
: 2.4mb
User
:
崔光涛
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