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Description: 大数相乘、计算时间、josep问题、计算JC、分形图形-multiply large numbers, computation time, Josep, calculated JC, fractal graphics
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Size: 3574 |
Author: 张志明 |
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Description: 大数相乘，可以解决超过大整数的问题-multiply large numbers, can be resolved over the issue of large integer
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Size: 33565 |
Author: 李林骏 |
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Description: 大数相乘的源代码,使用C++在VC环境中实现.-multiply large numbers of the source code, the use of C in the VC environment to achieve.
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Size: 7875 |
Author: 刘志铭 |
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Description: 这是一个用c语言实现的2个32大数相乘，乘积为64.-This is a use of language c 2 32 multiply large numbers, the product of 64.
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Size: 922 |
Author: bolin.gong |
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Description: 大数相乘、计算时间、josep问题、计算JC、分形图形-multiply large numbers, computation time, Josep, calculated JC, fractal graphics
Platform: |
Size: 3072 |
Author: 张志明 |
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Description: 大数相乘，可以解决超过大整数的问题-multiply large numbers, can be resolved over the issue of large integer
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Size: 32768 |
Author: 李林骏 |
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Description: 大数相乘的源代码,使用C++在VC环境中实现.-multiply large numbers of the source code, the use of C in the VC environment to achieve.
Platform: |
Size: 7168 |
Author: 刘志铭 |
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Description: 大数相乘算法,使用C++语言在VC下实现.-large numbers multiply algorithm, the use of C language in the VC achieve.
Platform: |
Size: 3072 |
Author: 刘志铭 |
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Description: 这是一个用c语言实现的2个32大数相乘，乘积为64.-This is a use of language c 2 32 multiply large numbers, the product of 64.
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Size: 1024 |
Author: bolin.gong |
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Description: 文件包括RSA算法原程序及详细注释。可以实现使用1024位以上大素数进行加解密。其中包括大整数的加、减、乘、除、模幂运算，求逆元运算，以及大素数的判定等算法。稍做扩展即可在实际中应用。-Documents include the RSA algorithm for the original procedures and detailed notes. Can be achieved using more than 1024 large prime numbers for encryption and decryption. Including large integer add, subtract, multiply, divide, modular exponentiation computation, and inverse calculations, as well as the large prime numbers, such as algorithms to determine. Can be extended slightly in the actual application.
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Size: 112640 |
Author: wp |
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Description: 大数运算的设计与实现，大数加，减，乘，除，阶乘，幂，排列组合，进制转换-Computation of large numbers of design and realization of large numbers add, subtract, multiply, divide, factorial, power, permutation and combination, hexadecimal conversion
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Size: 2213888 |
Author: 谢新强 |
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Description: 大数乘法函数Multiply：
输入：两个任意长度的10进制整数序列字符串，如4567891234567890或者101
输出：一个10进制整数序列字符串，为所输入两个数的乘积，如4567891234567890*101=461357014691356890
-Multiplicative function of large numbers Multiply: Input: two arbitrary length integer sequence of 10 hexadecimal string, such as 4567891234567890 or 101 Output: an integer sequence of 10 hexadecimal string, for the importation of the product of two numbers, such as 4567891234567890* 101 = 461357014691356890
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Size: 1024 |
Author: 李明 |
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Description: 能实现大数的乘法运算，大数运算在各个方面都要用到-Can realize the multiplication of large numbers, large numbers in the various aspects of computing should be used
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Size: 1024 |
Author: xiongwei |
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Description: 大数乘法,计算大整数的乘法的c++源代码-Multiplication of large numbers to calculate the multiplication of large integer c++ Source code
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Size: 1024 |
Author: 高岩 |
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Description: RSA公钥加密算法(基于大整数的分解难实现的，包括大整数的加、减、乘、除，加密，解密等)-RSA public key encryption algorithm (based on the decomposition of large integers difficult to realize, including the large integer add, subtract, multiply, divide, encryption, decryption, etc.)
Platform: |
Size: 4096 |
Author: xu |
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Description: 大整数乘法
poj 2980
比一般的算法快一点点哦-Poj 2980 large integer multiplication
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Size: 1024 |
Author: 马超 |
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Description: 本程序围绕大整数编程，程序能够实现大整数的加、减、乘、除取余等运算。-This program around the big integer programming, the program can achieve large integer add, subtract, multiply, in addition to taking over other operations.
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Size: 1024 |
Author: 陈源 |
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Description: 汇编 大数相乘
include irvine32.inc
value3=value1*value2
.data
str1 byte "请输入16进制的32位整数(乘数)（8个）：",0
str2 byte "请输入16进制的32位整数(被乘数)（8个）：",0
str3 byte "相乘结果为：",0
value1 dword ? 乘数
value2 dword ? 被乘数
value3 dword 2 dup(0) 结果
m dword 0
用m的值表示两数相乘的情况：0：正*正 1：正*负或负*正 2：负*负-Compilation multiply large numbers the the include irvine32.inc value3 = value1* value2 called data str1 byte " Please enter 16 hex 32-bit integers (multiplier) (8):" , 0 str2 byte hexadecimal 32-bit integers (multiplicand) (8): " , 0 str3 byte multiplying the result:" , 0 value1 dword? multiplier value2 dword? dup Multiplicand value3 dword 2 (0) result m dword 0 expressed multiplying two numbers: 0: n* n-1: positive* negative or negative value of m* n 2: Negative* Negative
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Size: 1024 |
Author: 念迹 |
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Description: 大数相乘使用String操作实现防止溢出-Multiply large numbers C++ achieve, to prevent overflow. String operations
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Size: 1024 |
Author: Ender |
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Description: 大数相乘的算法，本例是利用三个栈和一个队列来实现的大数相乘，此思想较为复杂点-Multiply large numbers algorithm, in this case is the use of three stack and a queue to achieve multiply large numbers, this ideology is more complex point
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Size: 307200 |
Author: 诚可贵 |
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