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Description: 代码模拟了龟兔赛跑爬山的情况,其中有个时钟触发设置每秒执行一次循环,乌龟的规则是:50% 的机会快走(右移三格) 20% 的机会下滑(左移六格) 30% 的机会慢走(右移一格).
兔子的规则是:20% 的机会睡觉(不移动) 20% 的机会大跳(右移九格) 10% 的机会大滑(左移十二格) 30% 的机会小跳(右移一格) 20% 的机会小滑(左移两格).
其中最先走到整 70 格的胜利,超过 70 格的从头开始 程序在一条线上打印了龟兔移动的轨迹,当两者重合时打印 P 乌龟用 G 表示,兔子用 T 表示.
-code to simulate the hand of the mountain, which has a clock installed trigger a cycle per second, turtle is a rule : 50% of the opportunity to leave (three grid shift to right) 20% chance of decline (6 bits grid) 30% chance of walking (a shift to right Lattice). rabbit is a rule : 20% of the opportunity to sleep (mobile) 20% chance of play (9 Georgia shift to right) 10% of the opportunities in Waterloo (12 bits Lattice) 30% chance of a small jump (shift to right a grid) 20% chance of a small slip (2 bits grid). the first of them go the whole 70 Lattice victory over 70 grid start again from scratch in a process of the turtles online print rabbit mobile track, when the two P Print coincides with the G turtles, rabbits with T said.
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Size: 1273 |
Author: 单士占 |
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Description: St7565P液晶控制芯片在128X64点阵下的51环境控制程序，经过测试应用，无问题-St7565P LCD control chip in 128X64 lattice under the 51 environmental control procedures, After testing applications, no problem! !
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Size: 2669 |
Author: 田军卓 |
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Description: PCI接口的Verilog源代码-PCI connection Verilog source code
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Size: 397312 |
Author: 包盛花 |
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Description: St7565P液晶控制芯片在128X64点阵下的51环境控制程序，经过测试应用，无问题-St7565P LCD control chip in 128X64 lattice under the 51 environmental control procedures, After testing applications, no problem! !
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Size: 2048 |
Author: 田军卓 |
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Description: 12232F是内置8192个16*16汉字点阵字库的液晶点阵控制器，本文介绍了其使用方法。-12232F is built 8192 16* 16 Chinese lattice character dot-matrix LCD controller This paper describes its use.
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Size: 634880 |
Author: yuflyer |
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Description: 针对CPLD的所有应用，使自己花了好长时间才整理出来，分类-CPLD for all applications, so that spent their time before finishing well out of classification
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Size: 16572416 |
Author: 阚建峰 |
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Description: SPLC501液晶显示模组为128X64点阵，面板采用STN（Super Twisted Nematic）超扭曲向列技术制成并且由128 Segment和64 Common组成，LCM非常容易通过接口被访问。-SPLC501 liquid crystal display module for the 128X64 lattice, panel STN (Super Twisted Nematic) Super Twisted Nematic technology made by 128 Segment and 64 Common components, LCM is easy to be accessed through the interface.
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Size: 8110080 |
Author: 矿丁 |
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Description: 由文件input.txt提供输入数据。输入文件第1 行有2个正整数n和m（1<=n,m<=100），
表示仓库是n×m个格子的矩形阵列。接下来有n行，每行有m个字符，表示格子的状态。
S 表示格子上放了不可移动的沉重货物；
w 表示格子空闲；
M 表示仓库管理员的初始位置；
P 表示箱子的初始位置；
K 表示箱子的目标位置。
-Provided by the input data file input.txt. Line 1 input file there are two positive integers n and m (1 < = n, m < = 100), said the warehouse is a n × m rectangular grid array. Then there are n lines, each line has m characters, said the state lattice. Lattice S that can not be put on the movement of heavy goods w that free lattice M said that the initial location of the warehouse manager P said that the initial location of the box K said that the goal of the location of the box.
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Size: 3072 |
Author: 王加福 |
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Description: ★实验任务
正如你所知道的 s_sin 是一个贪玩的不得了的小 P 孩 QAQ，你也知道他最近很喜欢玩一
个叫做太阳帝国的原罪的策略游戏去年他已经和疯狂的 AI 交战了整整一年。而现在，战斗
的序幕又要拉开了。
在某个星球上，该星球由 n*m 个方格组成，每个方格中可能为 boss，s_sin，障碍，道
路，小怪。s_sin 想要去打爆 boss，假设他可以秒杀 boss，现在他的任务只需要到达 boss
所在的位置。如果 s_sin 想要到达某个方格，但方格中有小怪，那么必须打死小怪，才能到
达这个方格。假设 s_sin 只能向上、下、左、右移动一个格子，移动一步用时 1 个时间单位，
杀死小怪也用 1 个时间单位。假设 s_sin 很强壮，可以杀死所有小怪。
试计算 s_sin 到达 boss 位置至少需要多少时间。注意：障碍时不能通过的。
★数据输入
输入第一行为两个正整数 n，m (1 < =n，m< =100)， 表示该地图有 n 行 m 列。
接下来 n 行，每行 m 个字符：“.”代表道路 ， “a”代表 boss ， “r”代表 s_sin ，
“#”代表障碍，“x”代表小怪。-The experimental task
As you know s_sin is a fun not the small child P QAQ, you know he loves playing with a recently
A strategy game called the sins of a Solar Empire last year and he has mad at AI for a whole year. And now, the battle
Prelude to open.
On a planet, the planet by n*m squares which, as boss, s_sin, obstacle each square, road
The road, small strange. S_sin wants to hook boss, assuming he can Seckill boss, his task now only need to reach boss
Location. If s_sin wants to reach a square box, but have a little strange, so must kill mobs, to
Reach a square. Assume that s_sin only to the upper and lower, left, right movement of a lattice, move in 1 time units,
Kill mobs in 1 time units. Assume that s_sin is very strong, can kill all the mobs.
Calculate the s_sin arrives at the boss position at least how much time. Note: barrier to adoption.
Data input
The first input two positive integers n, m (=n < 1, m< =100), said the map with n M.
The next N lines, M char
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Size: 2048 |
Author: 王一丞 |
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Description: 手写汉字变形问题是非特定人脱机手写汉字识别中的关键同题。本文从预处理的角度探讨了直接从汉字点阵图像上矫正手写变形、减小属于同一类别的不同模式之I町差异的途径，提出了一种新的非线性规一化方法。该方法同时考虑了汉字笔画像素点和背量空白像素点，汉字点阵中的所有像素点均具有笔画密度描述，且将不同的像素点赋予不同的笔画密度，笔画密度时描述具有二维性、局部性，使得笔画密度的描述更为合理，规一化后的汉字点阵中笔画的分布更加趋向均匀．实验结果证实了本文方法的有效性。-The problem of handwritten Chinese character deformation is the key problem of non- specific person s offline handwritten Chinese character recognition. In this paper, we discuss the way of correcting the handwriting deformation directly the Chinese character lattice image and reducing the difference between the different patterns belonging to the same category the pretreatment point of view, and propose a new nonlinear normalization method. This method also takes into account the pixel of Chinese characters and the white pixels of the back volume. All the pixels in the Chinese word lattice have the description of the stroke density, and the different pixels are given different stroke density. The stroke density is described as having two dimensions , Localized, making the description of the density of strokes more reasonable, standardized distribution of Chinese characters in the distribution of strokes more evenly evenly. The experimental results confirm the effectiveness of the p
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Size: 193536 |
Author: 东方 |
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Description: 分析二维正方格子上的逾渗问题，通过编写程序，得到临界概率 P 及临界指数
(PS:程序功能简单介绍:yushen.m 中计算了 Pinf 和 p 的关系，yushenmain.m 调用 yushen.m 来 计算不同 p 下的 Pinf;yushenhuixuan.m 中计算了 Rs 和 p 的关系，yushenmain2.m 调用 yushenhuixuan.m 来计算不同 p 下的 Rs。具体的实现程序中均有注释。)(The percolation problem on two dimensional square lattice is analyzed, and the critical probability P and critical exponent are obtained by programming.
(PS: program functions simply: the relationship between Pinf and P is calculated in yushen.m, yushenmain.m is called yushen.m to calculate Pinf under different p; the relationship between Rs and P is calculated in yushenhuixuan.m, and yushenmain2.m invokes to calculate the differences under different P. There are annotations in the specific implementation program. ))
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Size: 43008 |
Author: 渡弘 |
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