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[OS programcircle

Description: 屏幕中央有一个半径为R1的大圆和一个同心的且半径为R2的小圆,同时在大圆和小圆中间均匀分布着12个与大圆和小圆相切的圆-The screen has a radius R1 of the great circle and a concentric radius R2 and the small round, while in the great circle and small round evenly distributed among 12 small round and the great circle and the circle tangent
Platform: | Size: 1024 | Author: 张毅 | Hits:

[Software EngineeringMATLAB-basic-intensive-training

Description: 运用MATLAB编程并结合simulink解决简单的电路问题。 自选题目:图1所示为典型的直流电阻电路[3], 含有电压控制的受控电流源VCCS,其中,R1=1Ω,R2= 2Ω, R3=3Ω,US=10V, IS=15A, VCCS= ,现需分析计算电流i1和电压u2 -Combined with the use of MATLAB simulink program to solve simple circuit problems. Optional Title: Figure 1 shows a typical DC resistance of the circuit [3], with voltage-controlled current source controlled VCCS, which, R1 = 1Ω, R2 = 2Ω, R3 = 3Ω, US = 10V, IS = 15A, VCCS =, now need to be analyzed to compute the current and voltage u2 i1
Platform: | Size: 99328 | Author: weihao | Hits:

[Windows MobileCameraDemo

Description: 6410 WinCE6.0 R2 上的CAMERA 程序的源码,有很大的参考价值-6410 WinCE6.0 R2 on the CAMERA program source code, there is a great reference value
Platform: | Size: 225280 | Author: 李套 | Hits:

[Embeded Linuxs3c6410-yuv-capture

Description: 自己开发的基于华恒S3C6410-R2开发板的yuv图像采集程序,提供c源程序和MAKEFILE,头文件开发板配套资料有,使用时.c文件要改名为cam2fb.c,已产品化-Their development huaheng S3C6410-R2 based on development board yuv image capture program, providing c source code and MAKEFILE, the first development board supporting data files are, used. C file to be renamed cam2fb.c, has products of
Platform: | Size: 2048 | Author: 杨在 | Hits:

[Embeded Linuxs3c6410-h264-encode-ok

Description: 已产品化代码,用华恒S3C6410-R2开发板采集视频并压缩为H264格式,不带IDR帧,提供c源程序和MAKEFILE,头文件开发板配套资料有,使用时.c文件要改名为cam2fb.c-Product of the code has been used huaheng S3C6410-R2 development board acquisition and compression for the H264 video format, without IDR frame, providing c source code and MAKEFILE, the first development board supporting data files are, used. C file to be renamed cam2fb . c
Platform: | Size: 2048 | Author: 杨在 | Hits:

[Embeded Linuxs3c6410-h264-IDR-encode-ok

Description: 这是上一个代码的优化,加了IDR帧编码,适合不稳定网络(如移动通信网),已产品化,基于华恒S3C6410-R2开发板采集视频并压缩为H264格式,带IDR帧,使用时.c文件要改名为cam2fb.c-This is a code optimization, plus the IDR frame coding for unstable networks (such as mobile communications network), has been product oriented, huaheng S3C6410-R2 based on development board capture and compression for the H264 video format, with IDR frames, use time. c file to be renamed cam2fb.c
Platform: | Size: 3072 | Author: 杨在 | Hits:

[SQL ServerSQLServer2008R2eBook

Description: SQL Server 2008 R2 e-book
Platform: | Size: 7987200 | Author: Ben | Hits:

[JSP/JavaJiaoChaShang

Description: 文本挖掘中交叉熵算法实现,通过词汇左右出现的概率来计算交叉熵-Text mining cross entropy algorithm,The task of part2of2speech iden t if icat ion is to au tomat ically assign a part2of2speech tag to an unknow n wo rd w ith emp ty part2of2speech info r2 mat ion. A part2of2speech iden t if icat ion algo rithm based on k2nearest2neighbo rs st rategy is p re2 sen ted in th is paper. The p relim inary experimen t,
Platform: | Size: 2048 | Author: mikepeng | Hits:

[SQL ServerPro-SQL-Server-2008-Service-Broker

Description: Pro Biztalk BAM 2009 - Guide to develop Service Broker solutions using Microsoft Service Broker of Microsoft SQL Server 2008 R2
Platform: | Size: 4497408 | Author: Coi | Hits:

[Windows DevelopPro-SQL-Server-2008-XML

Description: Pro Biztalk BAM 2009 - Guide to develop solutions with XML using XML Data type of Microsoft SQL Server 2008 R2
Platform: | Size: 4939776 | Author: Coi | Hits:

[Windows Developcpp1

Description: C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323 -C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323
Platform: | Size: 8192 | Author: bhavin | Hits:

[Othercpp2

Description: C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323 -C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323
Platform: | Size: 34816 | Author: bhavin | Hits:

[Windows Developnext-gemeratopm

Description: C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323 -C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323
Platform: | Size: 20480 | Author: bhavin | Hits:

[matlabchoice-of-radio-freq

Description: C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323 -C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323
Platform: | Size: 146432 | Author: bhavin | Hits:

[matlabVirtual-router

Description: C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323 -C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323
Platform: | Size: 21504 | Author: bhavin | Hits:

[matlabIndex

Description: C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323 -C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in which method being called? a. Base method b. Derived method.. Ans. b 2. For the following C program #define AREA(x)(3.14*x*x) main() {float r1=6.25,r2=2.5,a a=AREA(r1) printf("\n Area of the circle is f", a) a=AREA(r2) printf("\n Area of the circle is f", a) } What is the output? Ans. Area of the circle is 122.656250 Area of the circle is 19.625000 3. What do the following statements indicate. Explain. • int(*p)[10] • int*f() • int(*pf)() • int*p[10] Refer to: -- Kernighan & Ritchie page no. 122 -- Schaum series page no. 323
Platform: | Size: 26624 | Author: bhavin | Hits:

[matlabmmfilter

Description: 该文件主要用与R2探地雷达数据处理滤波,方便、简单、有效-The document is mainly used with the R2 GPR data processing filter, convenient, simple, effective
Platform: | Size: 2048 | Author: zhang | Hits:

[matlabrmswbackgr

Description: 该文件主要用与R2探地雷达数据处理滤波,方便、简单、有效-The document is mainly used with the R2 GPR data processing filter, convenient, simple, effective
Platform: | Size: 1024 | Author: zhang | Hits:

[matlabTM_model2d

Description: 该文件主要用与R2探地雷达数据处理滤波,方便、简单、有效-The document is mainly used with the R2 GPR data processing filter, convenient, simple, effective
Platform: | Size: 6144 | Author: zhang | Hits:

[ELanguageLR-parser

Description: LR分析器设计 给定说明语句的拓广文法G[S ]如下: (0) S ->S (1) S->v I:T (2) I->I,i (3) I->i (4) T->r 其中v代表终结符var,r代表real。 其识别规范句型活前缀的DFA及LR(0)分析表如下: 输入 状态 ACTION表 GOTO表 v i , : r # S I T 0 S2 1 1 acc 2 S4 3 3 S6 S5 4 r3 r3 r3 r3 r3 r3 5 S9 8 6 S7 7 r2 r2 r2 r2 r2 r2 8 r1 r1 r1 r1 r1 r1 9 r4 r4 r4 r4 r4 r4 编程实现此文法的LR分析器,并设输入的文法的句子为: var i , i , i : real 给出输出结果 -LR parser design Given that statement, The Extension of the grammar G [S ] as follows: (0) S -> S (1) S-> v I: T (2) I-> I, i (3) I-> i (4) T-> r One representative of terminator v var, r representative of real. Living patterns of its identification Specification prefix DFA and LR (0) analysis as follows: Input GOTO table table status ACTION v i,: r# S I T 0 S2 1 1 acc 2 S4 3 3 S6 S5 4 r3 r3 r3 r3 r3 r3 5 S9 8 6 S7 7 r2 r2 r2 r2 r2 r2 8 r1 r1 r1 r1 r1 r1 9 r4 r4 r4 r4 r4 r4 Programming LR parser article law, and set the input sentence is the grammar: var i, i, i: real Given output
Platform: | Size: 212992 | Author: 浮云 | Hits:
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