Description: 报童问题的计算机仿真
％tm一轮实验的预定模拟天数
％t一轮实验的仿真天数累积值
％z订报量
％z 最优订报量
％g订报量z之上界
％s1损失值之累计值
％s最小损失值值
％r按概率分布产生随机售报量样本-newsboy problem of computer simulation% tm an experimental simulation of the target number of days a t% of the experimental days of accrued Simulation plot value volume%% z z Factory Workers optimal quantity% g subscription volume z% above the industry s1 loss value% cumulative value of the smallest losses's value % r value of the probability distribution of random reported sales volume samples Platform: |
Size: 824 |
Author:吴江华 |
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Description: 报童问题的计算机仿真
％tm一轮实验的预定模拟天数
％t一轮实验的仿真天数累积值
％z订报量
％z 最优订报量
％g订报量z之上界
％s1损失值之累计值
％s最小损失值值
％r按概率分布产生随机售报量样本-newsboy problem of computer simulation% tm an experimental simulation of the target number of days a t% of the experimental days of accrued Simulation plot value volume%% z z Factory Workers optimal quantity% g subscription volume z% above the industry s1 loss value% cumulative value of the smallest losses's value % r value of the probability distribution of random reported sales volume samples Platform: |
Size: 1024 |
Author:吴江华 |
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Description: 一个报童从报刊发行中心订报后零售，每卖一份报纸可赚钱a元；若报纸卖不出去，则退回发行处，每退一份要赔钱b元。每天报童卖出的份数是随机的，但报童可以根据以往卖报情况统计得到每天卖k份报纸的概率密度p(k)。
（1） 求报童每天期望收益达到最大（或损失达到最小）的定报量z。
（2） 改变参数a/b的值，观察订报量的最优值变化，画出变化曲线。
试画出仿真流程图，进行程序实现，并对仿真结果进行分析。
-A newsboy subscribe from the press after the retail distribution centers, each sale of a newspaper can make money a million if newspapers can not be sold, then returned to Issue Department, each retire to a loss of a b element. Newsboy sold shares in a day is random, but the newsboy can sell based on past statistics reported to be selling daily newspaper k the probability density p (k). (1) seeking newsboy expected profit per day to maximize (or minimize loss) reported that the volume of fixed-z. (2) change the parameters a/b values, subscribe to observe changes in the volume of the optimal value, draw curve. Simulation test to draw a flow chart for program realization, and simulation results for analysis. Platform: |
Size: 1024 |
Author:AZOTH |
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Description: 计算机仿真 报童问题的matlab实现，对于不同的分布情况，最优值的计算-Newsboy problem of computer simulation matlab to achieve, for different distribution of the calculated optimal value Platform: |
Size: 4096 |
Author:dyh |
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Description: 报童问题的计算机建模仿真：一个报童从报刊发行中心订报后零售，每卖一份报纸可赚钱a元；若报纸卖不出去，则退回发行处，每退一份要赔钱b元。每天报童卖出的份数是随机的，但报童可以根据以往卖报情况统计得到每天卖k份报纸的概率密度p(k)。-Newsboy problem of computer modeling and simulation: a newsboy from a press release after the retail center of newspaper subscriptions, a newspaper can make money for every sale a yuan if newspapers can not sell, then return the issue of office, each one to lose money b per return. Newsboys sell shares every day is random, but newsboy selling newspapers before the situation can be a daily statistical probability of selling newspapers density k p (k). Platform: |
Size: 7168 |
Author:小获 |
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Description: 关于报童问题的MATLAB仿真，其中分别进行了了均匀分布、负指数分布和高斯分布的方正。-MATLAB simulation on the newsboy problem, which had a uniform distribution, respectively, negative exponential distribution and the Gaussian distribution of the Founder. Platform: |
Size: 4096 |
Author:安 |
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Description: 报童购进数量应根据需求量确定，但需求量是随机的，所以报童每天如果购进的报纸太少，不够买的，会少赚钱；如果购进太多，卖不完就要赔钱，这样由于每天报纸的需求量是随机的，致使报童每天的收入也是随机的，因此衡量报童的收入，不能是报童每天的收入，而应该是他长期（几个月、一年）卖报的日平均收入。我们可以应用计算机模拟的方法 在模拟时间充分大的条件下（例如10000天），模拟每天的销售量，因而确定每天应买进多少报纸才能使平均总收入达到最大值。(The number of paper purchased should be determined according to the demanded. But the demand is random. So the newsboy will get less money if he buys too few or too much newspapers. The newsboy's daily income is random. Therefore, the income of newsboy cannot be measured by the income of a day, and should be his long term (one year) average income.We can use of the method of computer simulation while the condition of simulation time is sufficiently large (10000 days for example), simulate daily sales, and thus determine how much to buy every day to get the maximum average revenue.) Platform: |
Size: 9216 |
Author:lingberyl
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