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Description: 游戏说明： 牌的大小顺序： 大王，小王,A,K,Q,j,9,8,7,6,5,4,3,2 出牌规则： 每次只能出一张牌，每局开始时随机由其中一人先出牌，以后由上一次赢的玩家出牌。首家可以出任意一张牌。首家出牌后，下家所出的牌的花色要与首家的相同，大小不限。如确实没有花色相同的牌，则可以出其它的牌。 胜负判定： 当每人都出了一张牌后，如果花色相同，则比较两张牌的大小，牌大的赢.如果花色不同，则先出牌的赢。最后经过统计赢的次数最多的 玩家最终赢得比赛。 The rules is following: 1) The Cards RANK (big to small) is: A K Q J 10 9 8 7 6 5 4 3 2 2) Once only can play one Card,if the suit is same and the Rank is big,they win or lost if you no the suit ,you must play any card but your s always small, 3) Now i think you know the rules ! Goog Luck ! printf("Please choice your cards Color: 0 means spade 1 means hearts 2 means diamonds 3 means clubs :\n") -games : licensing the order : King, Wang, A, K, Q, j, 9,8,7,6,5,4,3,2 out licensing rules : each time out only one card, at the beginning of each Board random by one of the first to be out later last won by the player card. The first to be sent to an arbitrary license. The first card, the home under the license by the first matched with the same open-size. If they really do not matched the same card, can produce other card. The results found : When everyone out of a license, if the same colors, compared to the size of two licenses, the licenses won. If the colors were different, first-out licensing of winning. After winning the final statistics of the number of players up to the final whistle. The rules is following : 1) The Cards RANK (big to small) is : A K Q J 10 9 8 7 6 5 4 3 2 2) Once
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Author: 冰雨 |
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Description: Java 2 Development Kit 1.3.0 beta2 如果您是Java的程序开发者，您绝对不可以错过Java 2Development Kit这个程序开发套件！！Java在短短的数年之间已经成为开发网络应用程序不可或缺的一员，虽然Microsoft一直想要用ActiveX来取代Java的地位，但是因为Java卓越的效能以及高度的安全防护性，让Java一直稳居网络应用程序的王座。-if you are a program developer,you will absolutely never miss the Java 2Development Kit,Java has grown to a never missed member in the development of network programming in so short years,Microsoft always wants to use ActiveX to take place with Java,but Java still lead the way of network programming because of the excellent functions and high security.
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Author: 张轮 |
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Description: qt3.3.4 for win商用版开发包,配合Qt-Enterprise v3.3.4序列号生成器-qt3.3.4 for win business version development kits, with Qt-Enterprise v3.3.4 serial number generator
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Author: 高颖峰 |
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Description: 特别提示： 不要使用TC编译，因为TC最多只能编译2000行，而本程序有2500行，推荐使用工具Win-Tc。
程序写的比较仓促，bug很多在所难免，还望大家批评指正。
真诚的希望能和大家相互交流，共同提高。
去年暑假，本人闲来无聊写了一个C语言图形模式下的五子棋游戏，有如下功能：
1.使用鼠标控制
2.能够实现人机对战，并判断胜负
3.能够保存棋局和玩家所走的每一步，并且可以按步骤还原棋局
4.玩家能够悔棋、和棋、认输
5.保存每一个玩家的分数到一个文件中，可随时查看。
大概写了2500行，很多难点基本上都是靠自己琢磨的，比如判断胜负、人机对战、悔棋、还原棋局等等，由于本人五子棋水平低劣，所以写出的电脑的IQ也不高，大家可以尽情蹂躏。最后给大家一句忠告——别人的代码是可以看的，但课程设计还是要自己做的！
E-mail:zhongnanlifan@163.com
李凡
中南大学 计算机0304
程序写于2004.7.10
-Special Tip : Do not use TC compiler, as TC can only build up to 2,000 firms while the procedures are 2,500 firms use the tools Win- Tc. The procedure was relatively short, and many bug unavoidable, we also look criticized correct. A sincere hope that you will share together. Last summer, leisure, I wrote a boring C language graphics mode of 331 games, has the following functions : 1. use the mouse to control two. to achieve human-machine players, judge and 3 victory. to preserve and chess players are taking every step steps can be reduced by four chess game. players can he never cheat in spain, a draw in chess. Lose 5. every player kept the score to a document, they can always check. Writing about the 2500 trip, many difficulties are basically on their own pondering, for instance, to jud
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Description: this something useful at snmp network.It is famous person.It will be useful for you I guess.-this something useful at snmp network.I t is famous person.It will be useful for you I Facts ss.
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Author: wangjia |
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Description: 问题的提出：赌博游戏世界无所不在，其中“掷双骰”游戏家喻户晓，
其游戏规则如下：每次掷两个骰子，每个骰子的6面上分别标有1、2、
3、4、5、6，两个骰子停止滚动后，计算其向上的点数之和。假如首
次掷出后点数之和为7和11，那么玩家赢（庄家输）。假如首次掷出后
点数之和为2、3或12，那么玩家输（庄家赢）。假如首次掷出后点数
之和为4、5、6、8、9和10，那么这些数字会立即成为玩家的“目标点”
（即下次如遇到此点数为赢）。要想赢，必须不断地掷两个骰子，直到
点数与目标点数相等为止，但在这之前，假如不幸地掷出7点，那么玩
家马上就输，试编程模拟此游戏。-the problem : the world of gambling games omnipresent, "throwing two dice" game known its rules of the game are as follows : two each throwing dice, each of the six dice surface were labeled with 1, 2, 3, 4, 5, 6, two dice stopped rolling, the calculation of its progressive and Numbers. If the points after the first allocate the sum of 7 and 11, then the player wins (Makers T). If the points after the first allocate the sum of two, three or 12, then the players lose (Makers Win). If the points after the first allocate the sum of 4, 6, 8 and 9 and 10, So these figures will immediately become the player of the "target spots" (that is, the next case of this points to win). To win, to be constantly throwing two dice, until Decimal points with the same goal, but before this,
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Author: 萝卜 |
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Description: qt windows 下实现源码
-qt windows to achieve source
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Description: 《C++ GUI QT 3编程》
ISBN/ISSN：7-81077-731-9
北京航空航天大学出版社 2006
本书详细讲述了用Qt进行图形交互界面编程的各个部分。主要内容包括：入门、创建对话框、布局管理、事件处理、二维和三维图像等。
(加)JASMIN BLANCHETTE，(英)MARK SUMMERFIELD著
=====本书是使用QT3进行跨平台GUI程序开发的最佳参考书,此为配套源代码
- C++ GUI QT 3 Programming ISBN/ISSN :7-81077-731-9 Beijing University of Aeronautics and Astronautics Press 2006 book to describe in detail the use of Qt graphical interface to the various parts of programming. The main contents include: Introduction, create dialog, layout management, event handling, two-dimensional and three-dimensional images. (Plus) JASMIN BLANCHETTE, (British) MARK SUMMERFIELD forward ===== Qt3 book is the use of cross-platform GUI development the best reference books, such as matching source code
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Author: leee101 |
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Description: 1） 随机产生四个1-13的数，分别代表13张牌。
2） 提示玩家输入算式。
3） 判断玩家输入的表达式是否合法，其中算式中的四个数字只能是程序所给的四个数字，非法则回到1）。
4） 如果玩家认为这四张牌算不出24点（如：1，1，1，1），可只输入？，程序将判断这四张牌是否能得出24点，如果能，则程序将给出算式，如果不能，说明不能，并回到1）。
5） 当用户正确输入算式后，用“堆栈来求表达式的值”的原理 求出结果并判断是否为24，得出用户是输是赢的结果。
6） 询问用户是否继续，是则回到1），否则结束程序。
-1) randomly generated a number of four 1-13 representing 13 licenses.
2) Players are prompted to enter the formula.
3) to determine whether the players enter the legitimate expression, which in the formula can only be four digits of the four procedures to the number of illegal then back 1).
4) If the licensing of four players that can not count 24 points (for example: 1,1,1,1), can be input only? , The program will determine whether this card can come four 24-point, if we can, then the procedure will be given formula, if not, that can not, and return to 1).
5) When the user enter the correct formula, the use of "stack to seek expressions of value" principle and to determine whether the results obtained for 24, to draw customers to win or lose, it is the result.
6) asking the user whether or not to continue, is the return to 1), otherwise the end of the procedure
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Description: 这个开源的HTML文本编辑器可以让Web程序拥有如MS Word这样强大的编辑功能.
FCKeditor支持当前流行的浏览器如IE,Firefox,Netscape,Opera等戏中的坦克所遇到的障碍物主要有墙、炸弹(泡泡)。坦克的所到之处都可以留下炸弹，炸弹会在一定时间内爆炸，一旦对手被炸到，你就赢了~
-The open-source HTML text editor for Web program such as MS Word have this powerful editing functions. FCKeditor support popular browsers such as IE, Firefox, Netscape, Opera and other opera in the tanks of the main obstacles encountered in walls, bomb (bubble). Can be tanks went left of the bomb would be exploded in a certain period of time, once the bombing of the opponent, you win ~
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Description: 不用我多说大家都知道把！ 需要MYSQL数据库 ！-good good good good good good good good good good good good
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Author: 曙光 |
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Description: 21点游戏
规则：扑克牌A、2、3、4、、、、、、10、J、Q、K、大小鬼分别代表数字1、2、3、4、、、、、、10、11、12、13、21；
人和电脑轮流坐庄，庄家先发牌。
胜利条件：将所取牌点数相加凑成 "和"是21，谁先凑成21就胜出，如果没有人凑到"和"是21，就定"和"最接近21且小于21就胜出。
每人至多可取5张扑克牌。要注意"和"超过21者谁先爆掉也就是输了，如果都爆了，点数小的胜；当点数相同时，庄家胜。
-21-point game
Rules: playing cards A, 2,3,4 ,,,,,, 10, J, Q, K, representing the size of a ghost number 1,2,3,4 ,,,,,, 10,11,12,13 , 21
And the computer take turns in power, making the first licensing .
Victory conditions: to make up the sum of the points to take a license "and" is 21, who should make up 21 to win , if no one leans "and" is 21, on set "and" closest to and less than 21 to 21 to win .
Desirable up to 5 cards per person . Pay attention to " and" ringing off the hook more than 21 who is who should lose , if we burst , the small number of points wins when the same points , Zhuang Jiasheng .
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Author: 赵聪杰 |
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Description: 捕鱼达人游戏技巧：
1、在炮塔周围有一些游动非常缓慢的鱼，灯笼，魔鬼，乌龟等等，那些基本上全部是给你送分的，只要调准角度和等级连续打，基本可以拿下。
2、在把炮塔调到基本45度角度时候，通常可以看到一些向你的炮塔直冲而下的鱼，这些鱼的速度很快，遇到这种鱼，可以通常采取迎射，往往是2级和三级炮弹的连发，打鱼的两侧，而且要左右切换的攻击，特别是打魔鬼鱼的时候，炮弹一定要先打鱼的外侧翅膀，然后切换到左侧，连击，命中率很高。
3、从炮塔左侧出来的灯笼鱼，绕着你的炮塔很近游动的那些乌龟，尽量就不要浪费炮弹了，命中率很低，从炮塔左侧突然出现的鲨鱼，如果你平常喜欢用三级打，如果看到这样的鲨鱼，先用三级打一发，然后突然提高一级，连发两发，炮塔的位置一定要在45度角上，追射鲨鱼的前后鱼鳍，如果2发炮弹还搞不定，就不要浪费炮弹了。
4、在打离炮塔很近的乌龟的时候，先用平常打的炮弹打一发，然后突然升级，再打一发，打乌龟颈部，四肢和尾巴，命中率会高很多。-Fishing Daren game tips:
1, the turret around some very slow swimming fish, lanterns, devil, tortoise, etc., substantially all to you get points, as long as the alignment angle and level continuous playing, basically you can win.
2, in the turret to the basic 45-degree angle when usually you can see straight down to your turret fish these fish quickly encountered this kind of fish can usually take Ying shot, often 2 level and three shells on both sides of the bursts, fishing, and around switching attacks, especially playing devil fish, shells must first fishing outside of the wings, and then switch to the left side of the batter, The hit rate is high.
Out from the left side of the turret, lantern fish swimming around you very close to the turret turtle as far as possible not to waste shells, the hit rate is very low, the shark suddenly appeared from the left side of the turret, if you usually like to use three to play, if you see a shark, with three to play the situation, and then s
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Author: 853100013 |
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Description: 24点游戏：
基本要求及步骤：
1） 随机产生四个1-13的数，分别代表13张牌。
2） 提示玩家输入算式。
3） 判断玩家输入的表达式是否合法，其中算式中的四个数字只能是程序所给的四个数字，非法则回到1）。
4） 如果玩家认为这四张牌算不出24点（如：1，1，1，1），可只输入？，程序将判断这四张牌是否能得出24点，如果能，则程序将给出算式，如果不能，说明不能，并回到1）。
5） 当用户正确输入算式后，用“堆栈来求表达式的值”的原理 求出结果并判断是否为24，得出用户是输是赢的结果。
6） 询问用户是否继续，是则回到1），否则结束程序。
-24-point game: the basic requirements and steps: 1) random number four 1-13, respectively, on behalf of the 13 licenses. 2) prompts the player to enter formula. 3) to determine whether the players enter the expression legitimate four numbers in the formula can only program to four digits, illegally back to 1). 4) If the players four cards can not figure the 24 points (such as: 1,1,1,1), can only enter? , The program will be to determine whether these four cards can come up with 24 points, and if they can, then the program will be given in the formula, if not description can not, and back to 1). 5) When users correctly enter the formula, to evaluate the expression " stack" principle obtained results and determine whether the 24, come to the user to lose to win. 6) asks the user whether to continue, then back to 1), otherwise the end of the program.
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Author: 何春山 |
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Description: 现有4堆石子,两个人轮流取石子,他们有n种可能的取法,取法表示从第1堆取A1个石子,从第2堆中取B1个,第3堆取C1个,第4堆取D1个.如果取的时候某一堆的石子数比所要取的石子数要少,则这种取法是不可行的.取到最后没有可行取法的人就算输了.
现给出4堆石子的石子数目以及n种取法,请问如果两个人都采用最优取法,先取的人是赢还是输.-Four existing heap of stones, two people take turns stones, they have emulated n possible, take the A1 emulated said a stone from a pile of rubble taken from the second B1, 3rd stacker C1, 4th heap Take a D1 and if it' s a pile of stones take a few less than the number of stones to take it, then this is not feasible emulated Take to the last man, even if there is no feasible emulated lost. heap of stones now gives 4 n kinds of stones as well as the number of emulated, what if two people are using the optimal emulated, first take the people win or lose.
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Description: 2.2.1 程序功能简介
该程序是TICTACTOE游戏，棋盘为3*3，3个棋子连起来即为赢。输入参数时，若输入的数字超出边界在已有棋子的地方再输入，则提示出错，要求重新输入。
2.2.2程序设计要求
（1） 将程序改写成类；
（2） 将棋盘扩充成4*4；
（3） 统计输赢结果并打印输出；
（4） 选做：使游戏更生动（输赢条件相同）。
2.2.3课程设计说明
（1） 棋盘可用数组来定义，如Board[4][4]={0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}
（2） 题目要求把源程序封装在类中，需要编写一个类来封装所有相关函数和变量。同时对main主函数进行改写，以完成题目的要求。
-2.2.1 Program Features The program is TICTACTOE games, board 3* 3,3 chess is to win together. When the input parameters, beyond the boundaries of the digital input if there are pieces in place to re-enter, then prompts an error, requiring re-enter. 2.2.2 The program design requirements (1) to rewrite the program into categories (2) The board expanded into 4* 4 (3) and print out the results of statistical winning or losing (4) elected to do: make the game more vivid (win or lose the same conditions ). 2.2.3 Course Design Description (1) the board can be used to define an array, such as the Board [4] [4] = {0,0,0,0,0,0,0,0,0,0,0,0,0 , 0,0,0} (2) subject to the requirements of the source package in the class, you need to write a class to encapsulate all relevant functions and variables. While the main primary function rewritten in order to complete the requirements of the subject.
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Description: 小卡和欢总喜欢玩一个小游戏，游戏界面是4*4格子的棋盘，每个格子可以放一个棋子。
最开始的时候棋盘上只有一个棋子，叫 T 。
接下来欢总和小卡轮流放棋子，小卡的棋子是 X ，欢总是 O 。
如果有一行或一列或一条对角线上全部是某个选手的棋子（4个）或者3个他的棋子和 T ，这个选手就赢了，游戏结束。 如果所有格子都满了，没有人赢，以平局结束。-Small card and joy always like to play a little game, the game interface is a 4* 4 chessboard grid, each grid can put a piece. In the beginning only a pawn on the chessboard, called the ' T' . Then the sum of joy turns to put the pieces small card, a small card piece is ' X' , Huan always ' O' . If there is a row or a column or a diagonal line is all of a player' s pieces (4), or three of his pieces and the ' T' , the players win, the game ends. If all of the lattice are full, no one wins, ended in a draw.
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Author: ss |
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Description: 该程序是TICTACTOE游戏，棋盘为3*3，3个棋子连起来即为赢。输入参数时，若输入的数字超出边界或在已有棋子的地方再输入，则提示出错，要求重新输入。
1.2 课程设计要求
（1）将所需的数据和相应的函数封装在类中，改写程序使之结构化。
（2）将棋盘扩充成4*4的。
（3）统计输赢结果并打印输出。
（4）选做：使游戏更加生动。（输赢条件相同）-The program is a TICTACTOE game, the board is 3*3, the 3 pieces together that is to win. When the input parameters, if the input of the number than the border or in the place where there is a piece of re input, then prompted an error, the requirements of re input.
1.2 curriculum design requirements
(1) the required data and the corresponding functions are encapsulated in the class, and the program is structured to rewrite the program.
(2) to expand the board into 4*4.
(3) the statistical result and print output.
(4) choose to do: make the game more vivid. (or equal)
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Author: 周洋 |
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Description: 24点游戏是经典的纸牌益智游戏。从扑克中每次取出4张牌。使用加减乘除，第一个能得出24者为赢。（其中，J代表11，Q代表12，K代表13，A代表1）随机生成4个代表扑克牌牌面的数字字母，程序自动列出所有可能算出24的表达式，用户初始生命值为一给定值（比如3），初始分数为0。随机生成4个代表扑克牌牌面的数字或字母，由用户输入包含这4个数字或字母的运算表达式（可包含括号），如果表达式计算结果为24则代表用户赢了此局。使用计时器要求用户在规定时间内输入表达式，如果规定时间内运算正确则加分，超时或运算错误则进入下一题并减少生命值（不扣分）。所有成绩均可记录在TopList.txt文件中。(24 point game is the classic card puzzle game.Take 4 cards at a time from poker. Use the first 24 can be reached add, subtract, multiply and divide, to win. (of which J stands for 11, Q stands for 12, K stands for 13, A stands for 1), and programming addresses 24 games as required.
Basic requirements: randomly generated 4 cards on behalf of the surface of the card number letters, the program automatically list all possible to calculate the expression of 24, the expression evaluates to 24 representative users win this game.if the correct operation within the specified time, plus points, overtime or error in the next issue, and reduce the value of life (without deduction).
all grades can be recorded in the TopList.txt file.)
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Description: java MVC开发系统性平台完整版(综合各大开发)(Java MVC development system platform)
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Author: liu520 |
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