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Size: 4528 |
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Description: 计算任意多边形的面积算法-arbitrary polygon calculation algorithm of the area
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Size: 1177 |
Author: link |
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Description: 今天看了一下从fpga上下的曼彻斯特编解码的程序，感觉不是很清楚，仿真了一下，更迷茫了，大家看看为啥这程序要这么编呢？
程序比较长，不过写的应该还是不错的，看了后应该有收获。
总的思路是这样：
1 通过一个高频的时钟检测wrn信号，如果检测到上升沿，则表明开始编码，将输入的8位数据转为串行，并编码，然后输出。
2 定时信号是从高频时钟16分频后得到的，在wrn上升沿后16分频使能，在编码结束后禁止分频输出。
3 no_bits_sent记录串行输出的位数，应该是从0010到1001输出串行信号，到1010时编码结束，输出tbre表明编码完成。
问题是no_bits_sent在到了1010后还是会继续增加，直到1111，然后clk1x_enable 就为0，无法分频，clk1x就为一直流信号。这样当clk1x_enable再次为1的时候，no_bits_sent也不会增加，在1111上不变，clk1x_enable又会回到0了。
-today they simply watched from across the Manchester encoding and decoding process, not feeling very well, simulation a bit more confused, we look at procedures to be ready this series so? Procedures longer, but should still write good, it should have read harvest. The thinking is this : one by a high-frequency clock signal detection international, if detected rising edge, it indicates the beginning of coding will be entered into the eight to serial data and coding, and then output. Two timing signals from the high-frequency clock frequency 16 hours after the the international rising edge after 16 minutes frequency to enable the coding after the end of Prohibition-frequency output. 3 no_bits_sent record median serial output, it should be from 0010 to 1001 serial output signal to the end of
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Size: 5232 |
Author: 游畅 |
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Description: TIMER.ASM
*********
[ milindhp@tifrvax.tifr.res.in ]
Set Processor configuration word as = 0000 0000 1010 b.
a] -MCLR tied to VDD (internally).
b] Code protection off.
c] WDT disabled.
d] Internal RC oscillator [4 MHZ].
-TIMER.ASM ********* [milindhp @ tifrvax. tifr.res.in] Set Processor configuration AGREEMENT as d = 0000 0000 1010 b. a] - LR tied to VDD (inter nally). b] Code protection off. c] WDT disabled . d] Internal RC oscillator [4 MHZ].
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Size: 14638 |
Author: torry |
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Description: acm.zju.edu.cn第1074,1005,1010题-acm.zju.edu.cn that section 1074,1005,
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Size: 4795 |
Author: 张凯 |
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Description: 商业单位需要容易记忆的电话号码，有一些方法可以让电话号码变得更容易记忆。譬如，可以把电话号码写成单词或短语，如 TUT-GLOP 可以代表滑铁卢大学的电话。有时仅仅是把号码的一部分写成单词，如打 310-GINO 便可向 GINO 比萨饼店定购比萨。另一种让电话号码容易记忆的方法是将数字用一种容易记的方式组合起来，譬如 3-10-10-10 也可以代表 GINO 比萨饼店。
电话号码的标准形式是七位十进制数字，在它的第三位和第四位之间用连字符连接(例如：888-1200)。电话的键盘提供了字符于数字之间的映射关系，如下所示：
2
A、B和C
3
D、E和F
4
G、H和I
5
J、K和L
6
M、N和O
7
P、R和S
8
T、U和V
9
W、X和Y
Q 和 Z 没有映射到键盘，而连字符不需要被拨打并且可以根据需要添加和删除。TUT-GLOP 的标准形式是 888-4567，310-GINO 的标准形式是310-4466，3-10-10-10的标准形式也是 310-1010。
如果两个电话号码有相同的标准形式，那么这两个电话号码是相同的。-commercial units need easy to remember telephone numbers, there are ways to allow more telephone numbers easy to remember. For example, telephone numbers can be written words or phrases, such as pseudodynamic - GLOP can represent the University of Waterloo calls. Sometimes numbers is only part of the written word. if the fight 310-GINO will be able to GINO pizza shop ordering pizza. Another phone number so easy to remember the method is to use a number of easy to remember the combination. For example 3-10-10-10 can also represent GINO pizza shop. The telephone number is the standard form seven decimal digits. in its third and fourth between connecting with characters (for example 888-320-4234-1200). Telephone keyboard characters in the digital mapping between, as follows : 2 A, B and C, D,
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Size: 925 |
Author: 张日天 |
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Description: latest Linux driver for Realtek RTL8187 wireless NIC-latest Linux driver for Realtek RTL8187 wi reless NIC
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Size: 183546 |
Author: 熊光安 |
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Description: 1. Modify the Bug that WinZip Self-Extractor Occurs Error. So When Open WinZip Self-Extractor ==> Don t Infect it.
2. The Virus \"Basic\" Size is 1010 Bytes. -1. Modify the Bug that WinZip Self-Extract or Error Occurs. So When Open WinZip Self-Extra Hector ==
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Size: 10546 |
Author: liuyue |
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Description: ---实现的部分VHDL 程序如下。
--- elsif clk1x event and clk1x = 1 then ---if std_logic_vector(length_no) >= “0001” and std_logic_vector(length_no) <= “1001” then -----数据帧数据由接收串行数据端移位入接收移位寄存器---rsr(0) <= rxda --- rsr(7 downto 1) <= rsr(6 downto 0) --- parity <= parity xor rsr(7) --- elsif std_logic_vector(length_no) = “1010” then --- rbr <= rsr --接收移位寄存器数据进入接收缓冲器--- ...... --- end if---- achieve some VHDL procedure is as follows. --- Elsif clk1x event and then a clk1x = s --- if td_logic_vector (length_no)
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Author: 766 |
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Description: 这是一个关于汉诺塔的书机-HANOR on the book -
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Size: 10653 |
Author: 李博 |
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Description: ZJU ACM 1010排名第一的程序. 1025的高效程序
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Size: 1854 |
Author: Prinse Wang |
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Description: acm.pku.edu.cn/JudgeOnline上的题目1001到1010的十道题的代码，都是已经通过的，贴到.txt文件中的。
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Size: 7140 |
Author: captain |
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Description: acm.zju.edu.cn第1074,1005,1010题-acm.zju.edu.cn that section 1074,1005,
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Size: 4096 |
Author: 张凯 |
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Description: acm.pku.edu.cn/JudgeOnline上的题目1001到1010的十道题的代码，都是已经通过的，贴到.txt文件中的。-acm.pku.edu.cn/JudgeOnline on the topic of the 1001-1010 title 10 of the code, are already adopted and put into. txt files.
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Size: 7168 |
Author: captain |
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Description: Ejemplos de alertas y comandos con J2ME
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Size: 2048 |
Author: Jorge |
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Description: ACM 相关的，POJ 1000-1010的全部解答，程序十分完备 部分还有文字说明-ACM-related, POJ 1000-1010 all the answers, procedures, and there is still a very complete text description
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Size: 3641344 |
Author: 平凡 |
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Description: 大数相加。杭电ACM1000-1010题
http://acm.hdu.edu.cn/listproblem.php?vol=1-Add large numbers. Hangzhou Xinhua ACM1000-1010 title http://acm.hdu.edu.cn/listproblem.php?vol=1
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Size: 6144 |
Author: squirrel |
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Description: 杭州电子科技大学ACM平台练习题1009,1010解答
-Hangzhou University of Electronic Science and Technology of ACM platform exercises 1009 and 1010 answers
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Size: 1024 |
Author: wfs |
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Description: 正泰科技HE-1010变频电源上位机 c#-
Chint Technology HE-1010 Frequency Power PC c#
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Size: 93184 |
Author: wangmeng |
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Description: CSR BLE 1010 SDK GUID
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Size: 286720 |
Author: zhanweili |
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